Question

What is the temperature in Celcius of 3.33 moles of neon that occupies 13.4 liters under the pressure of 3 atmospheres. Input your answer without units.

Answer 1

Hey there!:

Number of moles = 3.33 moles of neon

Volume = 13.4 L

Pressure = 3 atm

R = 0.0821 L.atm/mol*K

Therefore:

T = 3.0 * 13.4 / 3.33 * 0.0821

T = 40.2 / 0.2734

T = 147 K

k in C :

ºC = K - 273

147 - 273

T = - 126ºC

Hope that helps!