Question

What is the solution to the system of equations below?

X+ 3y = 15
and 4x+ 2y = 30
O (6,3)
O (3,6)
O (7,-6)
O (-6, 7)

Answer 1

(6,3)

Explanation:

Here is the system of equations:

x+3y=15

4x+2y=30

Since we have x with a coefficient of 1 in the first equation, let's use substitution to solve this system.

In the first equation, subtract 3y from both sides

x=-3y+15

now substitute -3y+15 as x in the second equation, and solve for y

4(-3y+15)+2y=30

do distributive property

-12y+60+2y=30

combine like terms

-10y+60=30

subtract 60 from both sides

-10y=-30

divide by -10

y=3

Now, substitute y as 3 into either one of the equations to solve for x.

For example, let's use x=-3y+15

x=-3(3)+15

multiply

x=-9+15

x=6

The answer is x=6 and y=3. As a point it's (6,3)

Hope this helps!