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Which answer best describes the complex zeros of the polynomial function?

f(x)=x3−x2+6x−6




The function has two real zeros and one nonreal zero. The graph of the function intersects the x-axis at exactly one location.


The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.


The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly two locations.


The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.

User Tom Leese
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8.4k points

2 Answers

0 votes

Answer:

B.) The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Step-by-step explanation:

Which answer best describes the complex zeros of the polynomial function? f(x)=x3−x-example-1
User Kmera
by
7.9k points
3 votes

Answer: The correct option is 2.

Step-by-step explanation:

The given polynomial is,


f(x)=x^3-x^2+6x-6

By rational root theorem 1 and -1 are possible roots of all polynomials.

put x=1


f(x)=(1)^3-(1)^2+6(1)-6=0

Since the value of f(x) is 0 at x=1. So 1 is a real root of the polynomial.

Divide the given polynomial by (x-1) using synthetic division method.


f(x)=(x-1)(x^2+6)

Equate each factor equal to 0.


x=1


x=\pm√(-6)

So, the given polynomial have one real root and 2 non real roots. Since the function have one real root therefore the function intersects the x-axis at exactly one location.

Thus, the correct option is 2.

Which answer best describes the complex zeros of the polynomial function? f(x)=x3−x-example-1
Which answer best describes the complex zeros of the polynomial function? f(x)=x3−x-example-2
User Awmross
by
7.5k points