Question

A 3.4-cm-diameter parallel-plate capacitor has a 2.0 mm spacing. The electric field strength inside the capacitor is 1.5×105 V/m .What is the potential difference across the capacitor?

Answer 1

Step-by-step explanation:

Given:

D = 3.4 см = 0.034 m

d = 2.0 mm = 2·10⁻³ m

E = 1.5·10⁵ V/m

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U - ?

U = E·d = 1.5·10⁵·2·10⁻³ = 300 V

Attention! Condition D is redundant in the condition!