178k views
0 votes
Write an equation in point-slope form for the line through the given point with the given slope.

(10, –9); m = –2


y + 9 = –2(x – 10)


y – 10 = –2(x + 9)


y – 9 = –2(x + 10)


y – 9 = –2(x – 10)

2.
Are the graphs of the lines in the pair parallel? Explain.

y = 6x + 9
27x – 3y = –81



No, since the slopes are different.


Yes, since the slopes are the same and the y-intercepts are different.


No, since the y-intercepts are different.


Yes, since the slopes are the same and the y-intercepts are the same.

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

; (–6, 5)













Are the graphs of the lines in the pair parallel? Explain.

y = x – 17
4x – 6y = –6



No, since the slopes are different.


No, since the y-intercepts are different.


Yes, since the slopes are the same and the y-intercepts are the same.


Yes, since the slopes are the same and the y-intercepts are different.

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

4x – 12y = 2; (10, –1)


y = 3x + 29


y = x + 7


y = x + 29


y = –3x + 29


Write the equation of a line that is perpendicular to the given line and that passes through the given point.

2x + 9y = –30; (–8, 0)


y = x + 36


y = x + 36


y = x + 36


y = x – 8

Write an equation in point-slope form for the line through the given point with the given slope.

(–3, –7); m =


y – 7 = (x + 3)


y – 7 = (x – 3)


y + 3 = (x + 7)


y + 7 = (x + 3)

Are the graphs of the lines in the pair parallel? Explain.

y = 4x – 4
24x – 4y = 96



Yes, since the slopes are the same and the y-intercepts are the same.


No, since the y-intercepts are different.


No, since the slopes are different.


Yes, since the slopes are the same and the y-intercepts are different.

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

–x + 5y = 14; (–5, –2)


y = x – 27


y = 5x – 27


y = –5x – 27


y = x – 15

Write an equation for the line that is parallel to the given line and that passes through the given point.

y = –5x + 3; (–6, 3)


y = –5x + 9


y = –5x + 27


y = 5x – 9


y = –5x – 27

Write an equation in point-slope form for the line through the given point with the given slope.

(8, –3); m =



y – 8 = (x + 3)


y – 3 = (x – 8)


y – 3 = (x + 8)


y + 3 = (x – 8)

Write an equation in point-slope form for the line through the given point with the given slope.

(–10, –1); m =


y + 10 = (x + 1)


y + 1 = (x + 10)


y – 1 = (x – 10)


y – 1 = (x + 10)

Write an equation for the line that is parallel to the given line and that passes through the given point.

y = x – 10; (–6, –29)


y = x + 14


y = x – 14


y = x – 14


y = x mc

User Adam Luter
by
6.0k points

2 Answers

6 votes

y -y1= m(x-x1) is in point slope form

y --9 = -2 (x-10)

y+9 = -2(x-10)

User Muers
by
5.5k points
5 votes

Answer:

Option a

y + 9 = –2(x – 10)

Explanation:

Given that a line passes through (10,-9) and slope =-2

We know that a point slope formula is


y-y_1 =m(x-x_1)\\

Here
x_1 =10:  y_1=-9:\\m=-2

Substitute this in the eqution to get


y-(-9) =-2(x-10)\\

Simplifying this


y+9=-2(x-10)

Option a) is right.

User Sherleen
by
6.5k points