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Subtracting rational expressions:

6 - x+5/(7x-5)(x+4)

Please show work

1 Answer

2 votes

Answer:


(42x^2+137x-125)/(7x^2+23x-20)

Step-by-step explanation:

You know that the sum of a number and a fraction is ...

... a + b/c = (ac +b)/c

Here, you have ...

... a = 6

... b = -(x+5)

... c = (7x-5)(x+4) = 7x² +23x -20

Then ...

... (ac +b)/c = (6(7x² +23x -20) -(x +5))/(7x² +23x -20)

... = (42x² +138x -120 -x -5)/(7x² +23x -20)

... = (42x² +137x -125)/(7x² +23x -20)

User Kartikey Singh
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