Question

A ping pong ball has a volume of approximately 3.4 cm^3 ; the Earth has a volume of approximately 1.1 x 1027 cm^3. Using scientific notation, calculate approximately how many ping pong balls would fit inside the Earth. Show and explain your work, rounding to the nearest tenth; answer in a complete sentence.

Answer 1

`(V_(Earth))/(V_(ping))= (1.1x10^(27) cm^3)/(3.4 cm^3)= 3.235x10^(26)`

So we can conclude that we can have approximately
`3.2x10^(26)` ping pong balls that would fit inside the Earth

Step-by-step explanation:

For this case we have the following info given:

`V_(Earth)= 1.1x10^(27) cm^3`

`V_(ping)= 3.4 cm^3`

And we want to know how many ping pong balls would fit inside the Earth, and in order to do this we can use the ratio between the two values, and if we do this we got:

`(V_(Earth))/(V_(ping))= (1.1x10^(27) cm^3)/(3.4 cm^3)= 3.235x10^(26)`

So we can conclude that we can have approximately
`3.2x10^(26)` ping pong balls that would fit inside the Earth

Answer 2

`\text{Answer: There are }3.2* 10^(23)\text{ ping pong balls would be required to fit inside the Earth.}`

Step-by-step explanation:

Since we have given that

Volume of a ping pong ball is given by

`3.4 cm^3`

Volume of earth is given by

`1.1* 10^(27)cm^3`

We need to find the number of ping pong balls .

Number of ping pong balls is given by

`(1.1* 10^(27))/(3.4)\\\\=3.2* 10^(26)`

`\text{So, there are }3.2* 10^(23)\text{ ping pong balls would be required to fit inside the Earth.}`