Question

Solve the system of equations. y=4x+8 x^2+7x-20

Answer 1

To solve the system of equations, substitute the value of y from the first equation into the second equation, combine like terms, factor the quadratic equation, set each factor equal to zero and solve for x, substitute the values of x back into the first equation to find the corresponding values of y. The solution to the system of equations is x = -7, y = -20 and x = 4, y = 24.

Step-by-step explanation:

To solve the system of equations:

y = 4x + 8

x^2 + 7x - 20

1. Substitute the value of y from the first equation into the second equation to get:
2. x^2 + 7x - 20 = 4x + 8
3. Combine like terms:
4. x^2 + 3x - 28 = 0
5. Factor the quadratic equation:
6. (x + 7)(x - 4) = 0
7. Set each factor equal to zero and solve for x:
8. x + 7 = 0 or x - 4 = 0
9. x = -7 or x = 4
10. Substitute the values of x back into the first equation to find the corresponding values of y:
11. If x = -7, then y = 4(-7) + 8 = -20
12. If x = 4, then y = 4(4) + 8 = 24
13. The solution to the system of equations is:
14. x = -7, y = -20
15. x = 4, y = 24

Answer 2

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