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What are the solutions to the quadratic equation 2x^2-8x-24=0
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What are the solutions to the quadratic equation 2x^2-8x-24=0

User Oleksandr Bondarchuk
by
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2 Answers

5 votes
An easy formula to use for this is -b+-√b^2-4(a×c)] /2(a) . This gave me ;

8+-√-8^2-4(2(-24)) /2(2)

8+-√64-4(-48)/4

8+-√64+192]/4

8+-√256]/4

8+-16/4

8+16=24/4=6

8-16=-8/4=-2

X=6&-2
User Jerico
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8.1k points
1 vote
2x^2-8x-24=0
Divide the whole equation by 2.
x^2-4x-12=0
Complete the square
x^2-4x+4-16=0
(x-2)^2 -16=0
(x-2)^2=16
Take the square root of each side.
(x-2)=4 and (-(x-2))=4
x=6 and x=-2
User Gerosalesc
by
9.0k points
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