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If x + 4y = 18 and x − 4y = 2, then x = ?

User Pmalbu
by
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2 Answers

3 votes

x + 4y = 18 and x − 4y = 2


I would use substitution

add the 2 equations together

x + 4y = 18

+ x − 4y = 2

-------------------------

2x + 0y = 20

2x = 20

divide each side by 2

2x/2 = 20/2

x = 10

Answer: x=1


User MoishyS
by
5.2k points
2 votes

Answer:

x=10

Explanation:

We have the system
\left \{ {{x+4y=18} \atop {x-4y=2}} \right. and we have to find the value of x,

we can clear y from both equations and then match them.

First equation:


x+4y=18\\4y=18-x\\y=(18-x)/(4)

Second equation:


x-4y=2\\4y=x-2\\y=(x-2)/(4)

Now matching both equations:


y=y\\(18-x)/(4)=(x-2)/(4)\\18-x=x-2

We can subtract x in both sides,


18-x=x-2\\18-x-x=x-2-x\\18-2x=-2

Subtract 18 in both sides,


18-2x=-2\\18-2x-18=-2-18\\-2x=-20

Divide both sides in (-2),


-2x=-20\\(-2x)/(-2) =(-20)/(-2)\\ x=10

Result: x=10

User Ecoffey
by
6.6k points