Question

Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq)+2Ag(s)

Answer 1

The equilibrium constant expression for the given equation is K = [Zn²+][Ag]².

Step-by-step explanation:

The substances that will appear in the equilibrium constant expression for the given equation are Zn²+(aq) and Ag(s). In this equation, Zn²+ is a reactant and Ag is a product. The equilibrium constant expression is written as K = [Zn²+][Ag]².

Answer 2

Hey there!

We Know that:

2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)

The equilibrium expression for the reaction is:

Kc = [ Zn⁺² ] / [Ag⁺ ]²

Hope that helps!