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What volume of H2O is formed at stp when 6.0g of Al is treated with excess NaOH? NaOH + Al + H2O —-> NaAl(OH)4 + H2 (g)
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What volume of H2O is formed at stp when 6.0g of Al is treated with excess NaOH? NaOH + Al + H2O —-> NaAl(OH)4 + H2 (g)

User Dannemp
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this is the formula and answer of this question
What volume of H2O is formed at stp when 6.0g of Al is treated with excess NaOH? NaOH-example-1
User Nicklas Nygren
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