Register
A wheelbarrow is used to lift a 200 lb loadThe length from the wheel axle to the center of the load is 2ft the length from the wheel and axle to the effort is 4.5 What is the ideal mechanical advantage
131k views
16 votes
A wheelbarrow is used to lift a 200 lb loadThe length from the wheel axle to the center of the load is 2ft the

length from the wheel and axle to the effort is 4.5 What is the ideal mechanical advantage

User Binder
by
3.0k points

1 Answer

5 votes

Calculate:

Ideal Mechanical Advantage (IMA)

IMA= Distance(effort force)/Distance(resistant force)

IMA= 5 feet/ 2 feet

IMA= 2.5

3. Static Equilibrium Calculations:

FE= Force of Effort Force

M= moment (Force x distance)

Moment Effort + Moment Resistance

∑ MFulcrum= 0

(200lbs)(2ft) + (5ft)(FE)= 0

5ft (FE) = 400 lbs/ft

FE= 80 lbs

A wheelbarrow is used to lift a 200 lb loadThe length from the wheel axle to the center-example-1
User Charrette
by
3.3k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.5m questions

4.4m answers

Other Questions

Implement this C program by defining a structure for each payment. The structure should have at least three members for the interest, principle and balance separately. And store all the payments in a structure
The steady-state data listed below are claimed for a power cycle operating between hot and cold reservoirs at 1200 K and 400 K, respectively. For each case, evaluate the net power developed by the cycle,
Name the author the "the journey to the centre of the earth"​
The fully corrected endurance strength for a steel rotating shaft is 42 kpsi, the ultimate tensile strength is 120 kpsi, the yield strength Sy=65 kpsi, and the fatigue stress correction factor Kf = 1.96.
Engine oil flows through a 25‐mm‐diameter tube at a rate of 0.5 kg/s. The oil enters the tube at a temperature of 25°C, while the tube surface temperature is maintained at 100°C. For a 100‐m long tube,
Link Copied!