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Write a quadratic equation in standard form such that -5 is it's only solution.

User Webaware
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\displaystyle\bf\\x_1=x_2=-5\\\\(x-x_1)(x-x_2)=0\\\\(x-(-5))(x-(-5))=0\\\\(x+5)(x+5)=0\\\\x^2+2\cdot x\cdot5 + 5^2=0\\\\\boxed{\bf x^2+10x + 25=0}



User David Neiss
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