Answer:
2. a. All three solutes are nonelectrolytes.
3. a. the solution of solute X
Explanation:
The freezing point depression (ΔTf) and boiling point elevation (ΔTb) are colligative properties: they depend on the numbers of particles.
The formula for ΔTf is
ΔTf = iKf·b
i is the van’t Hoff factor: the number of moles of particles you get from a solute.
For sucrose,
Sucrose (s) ⟶ sucrose (aq)
1 mole sucrose ⟶ 1 mol particles i = 1
For NaCl
NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)
1 mol 1 mol + 1 mol i = 2
For Ca(NO₃)₂
Ca(NO₃)₂(s) ⟶ Ca²⁺(aq) + 2NO₃⁻(aq)
1 mol 1 mol + 2 mol i = 3
===============
2. Freezing points
For a nonelectrolyte, i = 1.
Kf = 1.86 °C·kg⁻¹mol⁻¹
b = 1 mol/kg Calculate ΔTf
ΔTf = 1 × 1.86 × 1
ΔTf = 1.86 °C
Tf = Tf⁰ - ΔTf =0.00 °C – 1.86 °C = -1.86 °C
All the other solutions have lower freezing points, so the solutes must be electrolytes.
===============
3. Boiling points
The formula for ΔTb is
ΔTb = iKb·m
The solution with the highest boiling point will have the highest value of i.
In other words, the solution with the highest boiling point will be the one with the lowest freezing point.
That’s the solution of solute X.