Question

The sum of two consecutive odd interferes equals 12. What are they?

Answer 1

The two consecutive integers are 5 and 7

Explanation:

We know that the sum of two consecutive odd integers is equal to 12.

Assuming the first integer to be x and the second consecutive integer to be x+2, we can make the following equation:

`x+(x+2)=12`

`x+x+2=12\\\\2x+2=12\\\\2x=12-2\\\\2x=10\\\\x=(10)/(2) \\\\x=5`

The first integer is 5 so the second integer will be:

`x+2=5+2=7`

So the two consecutive integers are 5 and 7.

Answer 2

The sum of two consecutive odd integers equals 12

Let x represents the first odd integer

x+2 represents the second odd integer

Sum of first and second integer is x + (x+2)

The sum of two consecutive odd integers equals 12

So x +(x+2) = 12

x + x + 2= 12

2x + 2 = 12

Subtract 2 on both sides

2x = 10

Divide both sides by 2

x= 5

First odd integer = 5

second odd integer = x+2 = 5+2 = 7

Two odd integers are 5 and 7