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If x = (10 − 3i) and y = (3 − 10i), then xy= and xy=

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xy=(10-3i)(3-10i)=30-100i-9i-30=-109i

User ItsMeInMiami
by
7.3k points
3 votes

Answer:


xy = -109i

Explanation:

Given that:


x = 10 - 3i


y = 3-10i

where, i is the imaginary part

We have to find xy.


xy=(10-3i)(3-10i)


(10-3i)(3-10i) = 30-100i-9i+30i^2

We know that:
i^2 = -1

then;


(10-3i)(3-10i) = 30-100i-9i-30=-109i


xy =-109i

therefore, the product of x and y is, -109i

User Michael Marr
by
8.7k points

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