Question

A force of 12 N is applied to a block moving west. Another force of 26 N is being applied in the opposite direction. The block weighs 7kg. What is the net force and the acceleration?

Answer 1

`F_(Net) = 14N`

`a = 2m/s^2`

Step-by-step explanation:

Given

`Mass = 7kg`

`F_(west) = 12N`

`F_(opposite) = 26N`

Solving (a): The net force:

The force towards the west direction, will be regarded as negative while the opposite force will be regarded as positive.

So, the net force is:

`F_(Net) = -F_(west) + F_(opposite)`

Substitute values for the given forces

`F_(Net) = -12N + 26N`

`F_(Net) = 14N`

The net force is 14 N

Solving (b): Acceleration

Net force is calculated as:

`F_(Net) = Mass * Acceleration`

Substitute 7 kg for Mass and 14 N for Net force:

`14N = 7kg* a`

Make a the subject:

`a = (14N)/(7kg)`

`a = 2N/kg`

`a = 2m/s^2`

Hence, the acceleration is
`2m/s^2`