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Right triangle ABC has its right angle at C.

AC=12 and BC=5 .

Which trigonometric ratios are correct?

Select each correct answer.




cosA=12/13

tanA=12/13

tanB=5/12

sinB=12/13

sinA=5/13

2 Answers

6 votes

Answer:

CosA=12/13

SinB=12/13

SinA=5/13

Explanation:

I took the test :)

User Jisna
by
8.4k points
4 votes

The answers are:


cosA=(12)/(13)


sinB=(12)/(13)


sinA=(5)/(13)

The explanation is shown below:

1. By definition, when you have a rigth triangle, you can find the sine, cosine and tangent as following:


sine=(opposite)/(hypotenuse)\\cosine=(adjacent)/(hypotenuse)\\tangent=(opposite)/(adjacent)

3. To know the lenght of the hypotenuse you can apply the Pythagorean Theorem:


hypotenuse=\sqrt{12^(2)+5^(2)}=13

4. Therefore if AC=12, BC=5 and the right angle is at C, you can substitute values to find the sine, cosine and tangent of A and B:


sinA=(5)/(13)


sinB=(12)/(13)


cosA=(12)/(13)


cosB=(5)/(13)


tanA=(5)/(12)


tanB=(12)/(5)

Right triangle ABC has its right angle at C. AC=12 and BC=5 . Which trigonometric-example-1
User Lars Noschinski
by
8.9k points