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which of the following is the equation of a line that is perpendicular to 6x+3y=2 and that passes through the point (-2,4)

User Splendf
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1 Answer

3 votes

Answer:

The equation of the line is y = 1/2x + 5

Explanation:

To find a line perpendicular to the first line, we first need to find the slope of the first line. We can do this by solving for y.

6x + 3y = 2

3y = -6x + 2

y = -2x + 2/3

So, we know the original slope to be -2. Perpendicular lines have opposite and reciprocal slopes. Therefore, we know the new slope to be 1/2. Knowing this, we can use the slope and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 4 = 1/2(x + 2)

y - 4 = 1/2x + 1

y = 1/2x + 5

User Donnette
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