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Please select the best answer from the choices provided

Please select the best answer from the choices provided-example-1
User Unihedron
by
6.2k points

2 Answers

2 votes

Answer:

The correct answer option is b. 2.

Explanation:

We are given an expression
2^{(1)/(2)  }.2^{(1)/(2)  } and we are supposed to simplify it.

We know that
a^b.a^c= a^(b+c) which means if the bases are same, then the exponents are added up.

So here, our bases are same i.e. 2 so we will add up the exponents to get:


2^{(1)/(2)+ (1)/(2)  }

Taking the LMC of the exponents to get:


2^{(1+1)/(4)  }


2^{(2)/(2)  }

The fraction in the exponent gets cancelled so we are left with 2.

User Santosh Sahu
by
7.5k points
3 votes

we are given


2^{(1)/(2)}\cdot 2^{(1)/(2) }

we can use exponent formula


a^n \cdot a^m=a^(n+m)

now, we can use this formula


2^{(1)/(2)}\cdot 2^{(1)/(2) }=2^{(1)/(2)+(1)/(2) }

we can add exponent

and we get


2^{(1)/(2)}\cdot 2^{(1)/(2) }=2^{(1+1)/(2) }


2^{(1)/(2)}\cdot 2^{(1)/(2) }=2^{(2)/(2) }


2^{(1)/(2)}\cdot 2^{(1)/(2) }=2^(1)


2^{(1)/(2)}\cdot 2^{(1)/(2) }=2

So, option-B.......Answer

User Akzhan Abdulin
by
7.6k points