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1 vote
Which option lists am expression that is not equivalent to 4^2/3

0.25^2/3
0.25^-2/3
^3 square root of 16
(^3 square root of 4)^2

1 Answer

5 votes

remember that


x^{(a)/(b)}=\sqrt[b]{x^a}

also
x^(-a)=(1)/(x^a)

and
(a^b)^c=a^(bc)


so


4^{(2)/(3)}


first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so
0.25^{(-2)/(3)}=((1)/(4))^{(-2)/(3)=
\frac{1}{((1)/(4))^{(2)/(3)}}=4^{(2)/(3)}, which matches

3rd one,
\sqrt[3]{16}=\sqrt[3]{4^2}=4^{(3)/(2)}, which matches

4th one
(\sqrt[3]{4})^2=(4^{(1)/(3)})^2=4^{(2)/(3)} which matches


answer is
0.25^{(2)/(3)}

User Sonorita
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