Answer:
A) Common Ratio (r) = -2
B)
and
![a_1=-44](https://img.qammunity.org/2019/formulas/mathematics/middle-school/sf3w4mkjgequdrt3l5s4evpsccdmgilm49.png)
Explanation:
We are given a geometric series with some missing term.
Common ratio of geometric series is ratio two consecutive term.
Common ratio (r) =
![(22)/(-11)=-2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/4r960xqvt9v8yp9aoxmtkrp8lxmuezi36f.png)
Now we find the missing term.
First term of the series.
Common ratio r=-2
So,
![(-11)/(a)=-2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/flul6fvkc7izwuo407fwdm5u89i706f5t4.png)
So, a=5.5
![\therefore a_0=5.5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9kj2aobh1mnw3yg2o3cvf6xatpin7nvqpy.png)
Now we find second missing term
. This 4th term of the series
So,
![a_1=ar^3](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wu49dqkohriyjiqnxymc7sts73c8xzwwih.png)
where, a=5.5 and r=-2
![\therefore a_1=5.5(-2)^3 = 44](https://img.qammunity.org/2019/formulas/mathematics/middle-school/cp45ehkle22xt4jfz4yf9z2qacxflluz8p.png)