Question

A fireman's water hose shoots 320 kg of water each second against the door of a building. The velocity of the water is 20 m/s and the water strikes the door horizontally and doesnt bounce back. What average force is exerted by the stream of water?

Answer 1

`6400\ \text{N}`

Explanation:

`(m)/(t)` = Mass flow rate of water = 320 kg/s

`m` = Mass of water on the door

`t` = Time

`v` = Velocity of water on the door = 20 m/s

Force is given by

`F=(m)/(t)v\\\Rightarrow F=320* 20\\\Rightarrow F=6400\ \text{N}`

The average force is exerted by the stream of water is
`6400\ \text{N}`.