Question

I need help please now

Answer 1

`(10)/(21)`

Explanation:

(
`(2)/(3)` ×
`(3)/(7)`) + (
`(2)/(3)` ×
`(2)/(7)`)

Multiply
`(2)/(3)` times
`(3)/(7)` by multiplying numerator times numerator and denominator times denominator.

`(2x3)/(3x7)` +
`(2)/(3)` × (
`(2)/(7)`)

Cancel out 3 in both numerator and denominator.

`(2)/(7)` +
`(2)/(3)` × (
`(2)/(7)`)

Multiply
`(2)/(3)` times
`(2)/(7)` by multiplying numerator times numerator and denominator times denominator.

`(2)/(7)` +
`(2x2)/(3x7)`

Do the multiplications in the fraction
`(2x2)/(3x7)`

`(2)/(7)` +
`(4)/(21)`

The least common multiple of 7 and 21 is 21. Convert
`(2)/(7)` and
`(4)/(21)` to fractions with denominator 21.

`(6)/(21)` +
`(4)/(21)`

Since
`(6)/(21)` and
`(4)/(21)` have the same denominator, add them by adding their numerators.

`(6+4)/(21)`

Add 6 and 4 to get 10.

`(10)/(21)`

Hope this helps and have a great day! =D

Answer 2

10/21

Explanation:

multiply and then add