Given:
- There are two savings accounts - account A has $150 and account B has $300 to begin with.
- Malorie deposits $16 in account A and $12 in account B every month.
To Find:
The number of months where the balance of both is equal and the balance itself.
Solution:
In 37.5 months, the account balances in both accounts will be equal.
This balance will be equal to $750 in both account A and B.
Calculation:
Let x be the number of months where both the accounts have equal balance.
So, at the end of x months, 16x is the amount of money that will be added to account A (since $16 is added every month).
And the total amount at the end of x months will therefore be $(150+16x)
Similarly, at the end of x months, 12x is the amount of money that will be added to account B (since $12 will be added every month).
And the total amount at the end of x months will therefore be $(300+12x)
By our assumption, x is the number of months it will take for both the accont balances will be equal. Therefore, we have the equation
![150+16x=300+12x\\4x=150\\x=37.5](https://img.qammunity.org/2019/formulas/mathematics/college/b617mvmhottsqa6h6fjgf9g9fmm1rzcc23.png)
Therefore, in 37.5 months, the account balances in both accounts will be equal.
This balance will be equal to
i.e. $750 will be the balance in both account A and B.