Question

How many atoms are there in each of the following ?a.)1.50 mol Na c.) 0.250 mol. Sib.)6.755 mol Pb

Answer 1

`a) \: n = (N)/(NA) \\ 1.5 = \frac{x}{6.02 * \: {10}^(23) } \\ x = 1.5 * 6.02 * {10}^(23) \\ x = 9.03 * {10}^(23) \: atoms \: of \: Na`


`b) \: n = (N)/(NA) \\ 0.25 = \frac{x}{6.02 * \: {10}^(23) } \\ x = 0.25 * 6.02 * {10}^(23) \\ x = 1.505 * {10}^(23) \: atoms \: of \: Si \:`

`c) \: n = (N)/(NA) \\ 6.755 = \frac{x}{6.02 * \: {10}^(23) } \\ x = 6.755 * 6.02 * {10}^(23) \\ x = 40,6651 * {10}^(23) \\ x = 4.07 * {10}^(24) \: atoms \: of \: Pb \:`