Question

Find the values of x and y.

Answer 1

We have the isosceles triangle were y + 12 = 3x - 5,

and the equilateral triangle. Therefore 3x - 5 = 5y - 4.

From the first equation and the second equation we have:

y + 12 = 5y - 4 subtract 12 from both sides

y = 5y - 16 subtract 5y from both sides

-4y = -16 divide both sides by (-4)

y = 4

Substitute the value of y to the first equation:

4 + 12 = 3x - 5

16 = 3x - 5 add 5 to both sides

21 = 3x divide both sides by 3

x = 7

Answer: x = 7 and y = 4

Answer 2

We can solve the system of equations by substitution.Therefore, the solution to the system of equations is x=7, y=4.

From the diagram, we have the following system of equations:

3x - 5 = 5y - 4

y + 12 = 16

Solving the second equation for y, we get:

y = 4

Substituting this value of y into the first equation, we get:

3x - 5 = 5(4) - 4

3x - 5 = 20 - 4

3x = 21

x = 7

Therefore, the values of x and y are x = 7 and y = 4.