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Byron purchased a box of candy at the store.On his way home he ate 1/4 of the candy in the box.At dinner with friends later that night he served 1/2 of what was left.If there are 6 chocolates now left in the box, how many did the box contain to start with.

User Pdjota
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2 Answers

1 vote

So gonna do opposites

6+6=12

12= 3/4th of the entire box

4=1/4th of the entire box

12+4=16

There was 16 chocolates originally.

User Puneet Gupta
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5 votes

Answer: The number of candies that the box contain to start with is 16.

Step-by-step explanation: Given that Byron purchased a box of candy at the store. On his way home he ate one-fourth of the candy in the box and at dinner with friends later that night he served half of what was left.

We are to find the number of candies that the box contain to start with if there are only 6 candies left in the box.

Let c represents the number of candies in the box to start with.

So, on his way home, number of candies ate by Byron is given by


n_w=(1)/(4)c=(c)/(4).

Now, at the dinner, number of candies ate by Byron and his friends is


n_d=(1)/(2)*\left(c-(c)/(4)\right)=(1)/(2)*(3c)/(4)=(3c)/(8).

Since only 6 candies left in the box, so we have


c-n_w-n_d=6\\\\\Rightarrow c-(c)/(4)-(3c)/(8)=6\\\\\\\Rightarrow (8c-2c-3c)/(8)=6\\\\\\\Rightarrow (3c)/(8)=6\\\\\\\Rightarrow c=(6*8)/(3)\\\\\Rightarrow c=16.

Thus, the number of candies that the box contain to start with is 16.

User Francesco Casula
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