Question

Find the vertex of the parabola?

Answer 1

The vertex of the parabola
`y=ax^2+bx+c` has coordinates

`x_v=-(b)/(2a)`

and

`y_v=ax_v^2+bx_v+c.`

In your case, for the parabola
`y=x^2-4x+6` the vertex has coordinates

`x_v=-(-4)/(2\cdot1)=2`

and

`y_v=2^2-4\cdot 2+6=4-8+6=2.`

Therefore, point (2,2) is the vertex of the parabola.

Answer: correct choice is B