9514 1404 393
Answer:
ED = 26; CF = 13; arc ED = 136°; arc HD = 68°; arc CE = 88°
QU = 8; QR= 16; arc ST = 114°; arc QR = 114°; arc XT = 57°
Explanation:
Chords the same distance from the center of the circle are the same length. Chords of the same length intercept arcs of the same angle measure. A radius perpendicular to a chord bisects it and the arc it subtends. The sum of arcs in a circle is 360°. These facts are used to solve the problems here.
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Circle J
ED = 2×GD = 26
CF = GD = 13
arc ED = arc CD = 136°
arc HD = 1/2 arc CD = 68°
arc CE = 360° - 2×136° = 88°
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Circle Y
QU = 1/2×ST = 8
QR = ST = 16
arc ST = arc QR = 1/2(360° -34° -98°) = 114°
arc XT = 1/2 arc ST = 57°