Let t hours be the time the second car is driving untill it overtakes the first car. The nfirst car is
hours on the road.
If the lead car is going 60 mph, then for the
hours it will go the distance
![60\cdot(t-1(1)/(2))\ m.](https://img.qammunity.org/2019/formulas/mathematics/college/3gj12gswbqy7nkmqw5gz8o8bra6eco5dnd.png)
If the second place car is going 70 mph, then for the
hours it will go the distance
![70\cdot t\ m.](https://img.qammunity.org/2019/formulas/mathematics/college/d4jjgi9g55ykamjdn5u1px8h5rk66k94oj.png)
These distances are equal, then
![60(t-1(1)/(2))=70t,\\ \\60t-60\cdot (3)/(2)=70t,\\ \\10t=90,\\ \\t=9\ hours.](https://img.qammunity.org/2019/formulas/mathematics/college/4vwi7hus3kcruv4wcirirret5mr73e3wze.png)
Answer: 9 hours