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In a rally race the lead car is ahead by 1 1⁄2 hours. If the lead car is going 60 mph and the second place car is going 70 mph and starts 1 1⁄2 hours after the lead car, how long will it take to overtake the leader?

User Tenhobi
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1 Answer

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Let t hours be the time the second car is driving untill it overtakes the first car. The nfirst car is
t-1(1)/(2) hours on the road.

If the lead car is going 60 mph, then for the
t-1(1)/(2) hours it will go the distance


60\cdot(t-1(1)/(2))\ m.

If the second place car is going 70 mph, then for the
hours it will go the distance


70\cdot t\ m.

These distances are equal, then


60(t-1(1)/(2))=70t,\\ \\60t-60\cdot (3)/(2)=70t,\\ \\10t=90,\\ \\t=9\ hours.

Answer: 9 hours

User Kwesolowski
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