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He sum of 1/6, 2/3, and 1/4 is

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Solution, (1)/(6)+(2)/(3)+(1)/(4)=(13)/(12)\quad \left(\mathrm{Decimal:\quad }\:1.08333\dots \right)


Steps:


(1)/(6)+(2)/(3)+(1)/(4)


\mathrm{Least\:Common\:Multiplier\:of\:}6,\:3,\:4:\quad 12


\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM},\\(2)/(12)+(8)/(12)+(3)/(12)


\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad (a)/(c)\pm (b)/(c)=(a\pm \:b)/(c),\\(2+8+3)/(12)


\mathrm{Add\:the\:numbers:}\:2+8+3=13,\\(13)/(12)


The\:Correct\:Answer\:Is\:(13)/(12)


Hope\:This\:Helps!!!


-Austint1414

User Chana
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8.7k points
4 votes

The LCD here is 12. Th,us, 1/6, 2/3 and 1/4 become:

2/12, 8/12 and 3/12.

Their sum is 13/12, or 1 1/12.

User Zlinks
by
8.7k points

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