Question

The temperature of a gas increased from 398K to 455K inside of a rigid container. If the original pressure of the gas was 1.22atm, what will the pressure of the gas after the temperature change?

Answer 1

According to pressure law, at a constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin scale.

`(P1)/(T1) =(P2)/(T2)`

Here, P1 = Initial pressure of the gas = 1.22 atm

T1 = Initial temperature of the gas = 398 K

T2 = Final temperature of the gas = 455 K

P2 = Final pressure of the gas = ?

Therefore,

`P2 = ((P1)(T2))/(T1) =  ((1.22)(455))/(398) atm = 1.39 atm = 1.4 atm`

Therefore, the required pressure of the gas after the change in temperature is 1.4 atm.