Question

If a Geiger counter that is 1 m away from a small source reads 50 counts per minute, what will its reading be 2 m from the source?

Answer 1

as the amount of radiation received is proportional to 1/d^2

2m from source

for 1m readings are 50 count per minute

for 2m = 50 / (2)^2

50 / 4 = 12.5 count per minute

Answer 2

`12.5counts/min`

Step-by-step explanation:

Hello,

In this case, the radiation from a point source follows an inverse-square law wherein the quantity of radiation is proportional to 1/d², where d is distance. Therefore, 2 m away from the source, the counts will be:

`Counts/min=(50counts/min)/(2^2) =12.5counts/min`

Best regards.