173k views
2 votes
Let f(x) = x2 – 16 and g(x) = x + 4. Find fg f g and its domain.

2 Answers

4 votes

Answer: x+4; all real numbers except =-4

Step-by-step explanation:

f(x)/g(x) = (x2-16)/(x+4)

The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)

We can simplify by factoring the numerator:

(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)

The domain is the same as the original expression: all real numbers except x = -4

User Hhh
by
6.5k points
2 votes

Answer: fg
=x^3+4x^2-16x-64 and


Domain: All real number. All real number or
(-\infty,\infty)



Step-by-step explanation:


fg means product of two given function f(x) and g(x)


where,


f(x)=x^2-16 and
g(x)=x+4


Now, we have to find fg


So, fg=
f(x)* g(x)


Substitute f(x) and f(x)



\Rightarrow (x^2-16)(x+4)


Using distributive property simplify above expression and we get,


\Rightarrow x^3+4x^2-16x-64


We can see it is cubic polynomial. So, domain of cubic polynomial is all real number.

Domain: All real number or
(-\infty,\infty)



User GionJh
by
6.6k points
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