Answer: At 24 February, 2014 the population gets twice of its initial population.
Step-by-step explanation:
Since we have given that
The population for Alpha City, t years after January 1, 2004 is given as
![P(t)=0.3t^2+6t+80](https://img.qammunity.org/2019/formulas/mathematics/middle-school/s697qc9gaumqlrcik7flh1h4gde8k9dekr.png)
First we find out the initial population, i.e. t=0,
So, our quadratic equation becomes,
![P(0)=0+0+80=80](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8jlpjje6016byh0newciheih21det7nm3p.png)
According to question, we have said that if the population has twice its initial population, then it becomes
![P(t)=2* 80=160](https://img.qammunity.org/2019/formulas/mathematics/middle-school/cd4cl0x7urwbvus1z61t6ala4mfuhthjvs.png)
So, time taken to reach this above mentioned population is given by
![160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{Using quadratic formula ,we get }\\\\t_(1,\:2)=(-60\pm √(60^2-4\cdot \:3\cdot \:800))/(2\cdot \:3)\\\\t=-29.14\ and\ t=9.149](https://img.qammunity.org/2019/formulas/mathematics/middle-school/goyixl7jpg2taabncwey3m1e9dewkaql7b.png)
Now, we know that time can't be negative so, we take t=9.149 years.
Hence, At 24 February, 2014 the population gets twice of its initial population.