What is the equation of the line that passes through (-3,-7) and (8,-7)?

asked Nov 27, 2019 50.2k views

3 votes

by Ingen

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6 votes

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)$

We have the points (-3, -7) and (8, -7). Substitute:

$m=(-7-(-7))/(8-(-3))=(0)/(11)=0\\\\y-(-7)=0(x-(-3))\\\\y+7=0\to y=-7$

WinterChilly answered Dec 3, 2019

8.5k points

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