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−15x+4≤109 OR −6x+70>−2

User Drealmer
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2 Answers

1 vote

Answer:

All values of x are solutions

Explanation:

for khan

User Fred August
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-15x+4\leq109\qquad\text{subtract 4 from both sides}\\\\-15x\leq105\qquad\text{change the signs}\\\\15x\geq-105\qquad\text{divide both sides by 15}\\\\\boxed{x\geq-7}\\or\\-6x+70>-2\qquad\text{subtract 70 from both sides}\\\\-6x>-72\qquad\text{change the signs}\\\\6x<72\qquad\text{divide both sides by 6}\\\\\boxed{x<12}\\\\Answer:\ \boxed{-7\leq x<12}

User Melihovv
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