Question

What gcf of the numerator and denominator in the following fraction? 21m^2n/ 28mn^2

Answer 1

`21m^2n=3\cdot\boxed{7}\cdot\boxed{m}\cdot m\cdot\boxed{n}\\\\28mn^2=2\cdot2\cdot\boxed{7}\cdot\boxed{m}\cdot\boxed{n}\cdot n\\\\GCF(21m^2n,\ 28mn^2)=\boxed{7}\cdot\boxed{m}\cdot\boxed{n}=7mn\\-------------------------\\\\(21m^2n)/(28mn^2)=(7mn\cdot 3m)/(7mn\cdot4n)=(3m)/(4n)`