Question

PLEASE HELP ME FIGURE THIS OUT 1.........

Answer 1

Answers: a = III, b=positive, c= π/6, d=C, e=√3

a)
`(19\pi)/(6) - (12\pi)/(6) = (7\pi)/(6)` which is located in Quadrant III.

b) cos is negative and sin is negative so cot (cos/sin) is positive.

c)
`(7\pi)/(6) - \pi = (\pi)/(6)`

d) cot(π/6)

e) cot =
`(cos)/(sin)` =
`(-√(3) )/(-1) = √(3)`

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Answers: BC =
`√(17)`, AC =
`2√(17)`,

30°-60°-90° triangle has corresponding sides of: b - b√3 - 2b

AB = b√3

AB = √51

⇒ b√3 = √51

⇒ b = √17

BC = b

⇒ BC = √17

AC = 2b

⇒ AC = 2√17