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At least how many grams of copper must be alloyed with 387 g of pure silver to produce an alloy that is no more than 90% pure silver

User Jturi
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2 Answers

2 votes

Final answer:

At least 43 grams of copper must be alloyed with 387 grams of pure silver to produce an alloy that is no more than 90% pure silver.

Step-by-step explanation:

To determine the amount of copper needed to alloy with silver, we can set up a proportion:

Amount of Copper / Amount of Silver = Desired Copper-Silver Ratio

In this case, the desired purity of silver is no more than 90%. This means the desired ratio of copper to silver is:

Amount of Copper / 387 g = (100% - 90%) / 90%

Solving for the amount of copper:

Amount of Copper = (100% - 90%) / 90% * 387 g

Simplifying the equation:

Amount of Copper = 0.1 / 0.9 * 387 g

Amount of Copper ≈ 43 g

User Fatos
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5.9k points
2 votes

Let c = grams of copper to be added

(grams of silver) / (grams of copper and silver) < = .90

387+%2F+%28c+%2B+387%29+%3C=+.9

387+%3C=+.9%28c+%2B+387%29

387+%3C=+.9c+%2B+348.3

.9c+%3E=+387+-+348.3

.9c+%3E=+38.7


c+%3E=+43g

At least 43 grams of copper must be added

check:

387+%2F+%28c+%2B+387%29+%3C=+.9

387+%2F+%2843+%2B+387%29+%3C=+.9

387+%2F+430+%3C=+.9

.9+%3C=+.9

User Syed Arif Iqbal
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6.0k points