Question

PLEASE HELP ME FIGURE THIS OUT 1.

Answer 1

Answer:
`(7\pi)/(12)`, II,
`(5\pi)/(12)`

Explanation:

a)
`-(41\pi)/(12)`

Add 2π until you receive a positive number. 2π =
`(24\pi)/(12)`

`-(41\pi)/(12)` +
`(24\pi)/(12)` =
`-(17\pi)/(12)`

`-(17\pi)/(12)` +
`(24\pi)/(12)` =
`(7\pi)/(12)`

b)
`(\pi)/(2)` <
`(7\pi)/(12)` < π So it is located in Quadrant II

c) It is closest to the x-axis at π. π -
`(7\pi)/(12)` =
`(5\pi)/(12)`

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Answer: π, (-1, 0), A, 0

Explanation:

a) -7π

Add 2π until you receive a positive number.

-7π + 2π = -5π

-5π + 2π = -3π

-3π + 2π = -π

-π + 2π = π

b) Look at the Unit Circle to find that π is located at (-1, 0)

c) x = -1, y = 0, r = 1

sin θ =
`(y)/(r)`

d) sin θ =
`(y)/(r)` =
`(0)/(1)` = 0

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Answer: 7π

Explanation:

s = rθ

= 35
`((\pi)/(5))`

= 7π