Question

A zebra starts from rest and accelerates at 1.9 m/s, how far has the zebra gone after 5 seconds

Answer 1

23.8 m

Step-by-step explanation:

The distance travelled by the zebra can be calculated by using the equation:

`d=ut+(1)/(2)at^2`

where

u is the initial velocity

t is the time

a is the acceleration

For this zebra,

u = 0 since it starts from rest

`a=1.9 m/s^2` is the acceleration

Substituting t = 5 s, we find the distance travelled by the zebra:

`d=0+(1)/(2)(1.9)(5)^2=23.8 m`