154k views
3 votes
Three students are arguing over who can run the fastest.

Student A says that she can run 2/3 mile in six minutes.
Student B says that he can run 1/2 mile in four minutes.
Student C says that he can run 4/5 mile in eight minutes.
Type your answer as a number, and if necessary, use / for the fraction bar. Fractions should be expressed in lowest terms. What fraction of a mile can Student A, B and C run in one minute?

HELLLLLLLLLLLLP ASAP HONEUU BOO BOO

2 Answers

3 votes

Answer:

Student-A:

mile/min

Student-B:

mile/min

Student-C:

mile/min

Step-by-step explanation:

Student-A:

she can run 2/3 mile in six minutes

so,

total distance is miles

total time =6 min

we can use formula

speed=(total distance)/(total time)

mile/min

Student-B:

she can run 1/2 mile in 4 minutes

so,

total distance is miles

total time =4 min

we can use formula

speed=(total distance)/(total time)

mile/min

Student-C:

she can run 4/5 mile in 8 minutes

so,

total distance is miles

total time =8 min

we can use formula

speed=(total distance)/(total time)

mile/min

Explanation:

User Kvc
by
4.9k points
5 votes

Answer:

Student-A:


speed=(1)/(9) mile/min

Student-B:


speed=(1)/(8) mile/min

Student-C:


speed=(1)/(10) mile/min

Explanation:

Student-A:

she can run 2/3 mile in six minutes

so,

total distance is
(2)/(3) miles

total time =6 min

we can use formula

speed=(total distance)/(total time)


speed=((2)/(3) )/(6)


speed=(1)/(9) mile/min

Student-B:

she can run 1/2 mile in 4 minutes

so,

total distance is
(1)/(2) miles

total time =4 min

we can use formula

speed=(total distance)/(total time)


speed=((1)/(2) )/(4)


speed=(1)/(8) mile/min

Student-C:

she can run 4/5 mile in 8 minutes

so,

total distance is
(4)/(5) miles

total time =8 min

we can use formula

speed=(total distance)/(total time)


speed=((4)/(5) )/(8)


speed=(1)/(10) mile/min


User Mengdi Gao
by
5.5k points