Question

Consider the following reaction.

What is the conjugate base of CH3COOH

Answer 1

CH3COO–

Step-by-step explanation:

its the answer

Answer 2

According to Bronsted-Lowry theory of acids and bases, an acid is proton donor and a base is proton acceptor. When an acid loses the proton, it forms the conjugate base of the acid. Similarly when a base accepts a proton, it forms the conjugate acid if that base. A conjugate acid base pair differs by a single proton.

Given the weak acid
`CH_(3)COOH`. It can lose a proton to form the conjugate base.

`CH_(3)COOH(aq)-->CH_(3)COO^(-)(aq)+H^(+)(aq)`

Therefore, the conjugate base of
`CH_(3)COOH`is
`CH_(3)COO^(-)`.