Question

I need help with 3-4 above and the question below. Please urgent help! 100% correct answers?

An average depth for the human mouth is about 8 cm. We can model the mouth as an organ pipe that is open at the back of the throat. What are the wavelength and frequency of the first harmonic you can produce if your mouth is open? Assume v = 344 m/s.
16 cm; 2150 Hz
14 cm; 3000 Hz
20 cm; 1980 Hz
25 cm; 1500 Hz

Answer 1

#3

Length of the vocal chord is given as

`L = L_o`

speed of the sound is given as

`v = 344 m/s`

Lowest frequency is given as

`f = 220 Hz`

As we know that

`f = (v)/(4L_0)`

Now plug in all data in it

`220 = (344)/(4L_0)`

now the length is given as

`L_0 = 0.391 m = 39.1 cm`

#4

Length of the test tube is given as

`L = 14 cm = 0.14 m`

Since half of the tube is filled with water so length of resonating column is

`L_0 = 7 cm = 0.07 m`

speed of the sound is given as

`v = 344 m/s`

Lowest frequency is given as

`f = (v)/(4L_0)`

Now plug in all data in it

`f = (344)/(4* 0.07)`

now the length is given as

`f = 1230 Hz`

#given question

Length of the mouth is 8 cm

As we know that for the fundamental wavelength

`(\lambda)/(2) = L`

here L = 8 cm

so wavelength is given as

`\lambda = 2 * 8 = 16 cm`

now for the frequency we can use

`f = (speed)/(wavelength)`

`f = (344)/(0.16) = 2150 Hz`