Answer:
-4 and 3
Explanation:
since these are both lines, you can graph these with 4 lines by graphing the endpoints
for the top function, it goes from -4 to 3 including -4 but not including 3
if we evaluate f(-4), we get -4+4=0, so the point (-4,0) is on the graph (make it a fillled in dot since it is -4≤ and not -4<)
if we evaluate f(3), we get 3+4=7, so the point (3,7) is on the graph (make it an empty circle since this point is not included, since it is <3 and not ≤3)
connect those 2 points to get your first line
dxdd
for bottom function, it goes rom 3 to 6 including 3 but not incluing 6
if we evaluate f(3), we get 2(3)-1=6-1=5, so the point (3,5) is on te graph (make it a filled in dot since it is 3≤x and not 3<x)
if we evaluate f(6), we get 2(6)-1=12-1=11, so the point (6,11) is on the graph (make it an empty circle since this point is not incuded, since it is <6 and not ≤6)
connect those 2 points to get the bottom function