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PLEASE HELP!!! URGENT

The table shows the annual consumption of cheese per person in the U.S. for selected years in the 20th century.

Use a cubic model to estimate milk production in 1994.

A. 62.4
B. 58.4
C. 116.8
D. 54.4

PLEASE HELP!!! URGENT The table shows the annual consumption of cheese per person-example-1
User Jingwei
by
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1 Answer

7 votes

Answer-

The cubic equation-


f(x)=0.00009121x^3-0.00666099x^2+0.427014x+1.36845

Milk consumption in 1994 was 58.4 pounds.

Solution-

The general form of a cubic model is,


f(x)=ax^3+bx^2+cx+d

x = input variable = year - 2000 i.e number years after 2000

y = output variable = milk consumed in pounds

Then putting the values from the table,


2.592=a(3)^3+b(3)^2+c(3)+d


\Rightarrow 2.592=27a+9b+3c+d --------------------------1


13.301=a(39)^3+b(39)^2+c(39)+d


\Rightarrow 13.301=59319a+1521b+39c+d -------------2


20.41=a(56)^3+b(56)^2+c(56)+d


\Rightarrow 20.41=175616a+3136b+56c+d -------------3


63.359=a(97)^3+b(97)^2+c(97)+d


\Rightarrow 63.359=912673a+9409b+97c+d ------------4

Solving equations (1), (2), (3) and (4) simultaneously we get,


a=0.00009121,\\\\b=-0.00666099,\\\\c=0.427014,\\\\d=1.36845

So, the equation becomes,


f(x)=0.00009121x^3-0.00666099x^2+0.427014x+1.36845

In order to get the milk consumption in 1994, putting x=94


=0.00009121(94)^3-0.00666099(94)^2+0.427014(94)+1.36845


=(0.00009121)\cdot (830584)-(0.00666099)\cdot (8836)+(0.427014)\cdot (94)+(1.36845)


=58.4088

Therefore, milk consumption in 1994 was 58.4 pounds.

User Jeff Dallien
by
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