Question

Write an equation of the line, in point-slope form, that passes through the following points: (–2, 8), (3, –2).

A. y – 8 = –2(x + 2)
B. y – 8 = –2(x – 2)
C. y – 2 = –2(x + 8)
D. y – 8 = 2(x + 2)


What are the intercepts of the equation 3x + 4y = –12?

A. x-intercept: 4; y-intercept: 3
B. x-intercept: –4; y-intercept: –3
C. x-intercept: –3; y-intercept: –4
D. x-intercept: –12; y-intercept: –12

Answer 1

The equation of the line would be A) y - 8 = -2(x + 2)

Explanation:

In order to find the equation of the line, we need to start by finding the slope. We can do that with the slope equation.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-2 - 8)/(3 - -2)

m = -10/5

m = -2

Now that we have the slope at -2, we can plus in the first point into point-slope form and find the equation.

y - y1 = m(x - x1)

y - 8 = -2(x + 2)

QUESTION 2

Answer:

The correct answer is B) x-intercept = -4 and y-intercept = -3

Explanation:

We can tell this because the y-intercept is the value of y when x = 0. So we put 0 into x for the equation.

3x + 4y = -12

3(0) + 4y = -14

4y = -12

y = -3

Since B is the only answer with an y-intercept at -3, we know it to be the correct answer.